Java Program to Print Right Pascal Triangle Number Pattern
In this program we print a right Pascal triangle of numbers: the rows grow from 1 to 1 2 3 4 5 and then shrink back to 1, which looks like a triangle pointing to the right.
Like every pattern program, it is built from nested loops: the outer loop picks the row, and the inner loops print what goes on that row.
1. The Pattern
For 5 rows the program prints:
Pattern
1 1 2 1 2 3 1 2 3 4 1 2 3 4 5 1 2 3 4 1 2 3 1 2 1
2. How the Program Works
Here is what each printed line is made of when numberOfRows is 5:
| Line | Leading spaces | Printed after the spaces |
|---|---|---|
| 1 | 0 | 1 |
| 2 | 0 | 1 2 |
| 3 | 0 | 1 2 3 |
| 4 | 0 | 1 2 3 4 |
| 5 | 0 | 1 2 3 4 5 |
| 6 | 0 | 1 2 3 4 |
| 7 | 0 | 1 2 3 |
| 8 | 0 | 1 2 |
| 9 | 0 | 1 |
- Both parts print the numbers from 1 to
rowon each row. - Step 1 counts
rowup from 1 tonumberOfRows. - Step 2 counts
rowdown fromnumberOfRows - 1to 1. It starts one row lower so the longest row is printed only once. System.out.println()moves to the next line after each row.
3. Java Program
public class Pattern20 {
public static void main(String[] args) {
int numberOfRows = 5;
// Step 1: rows get longer, up to numberOfRows numbers
for (int row = 1; row <= numberOfRows; row++) {
for (int column = 1; column <= row; column++) {
System.out.print(column + " ");
}
System.out.println();
}
// Step 2: rows get shorter again, without repeating the longest row
for (int row = numberOfRows - 1; row >= 1; row--) {
for (int column = 1; column <= row; column++) {
System.out.print(column + " ");
}
System.out.println();
}
}
}
Output
1 1 2 1 2 3 1 2 3 4 1 2 3 4 5 1 2 3 4 1 2 3 1 2 1
4. Print the Pattern for Any Number of Rows
To let the user choose the size of the pattern, read the number of rows with a Scanner. The loops stay the same.
import java.util.Scanner;
public class Pattern20Input {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("Enter the number of rows: ");
int numberOfRows = scanner.nextInt();
scanner.close();
// Step 1: rows get longer, up to numberOfRows numbers
for (int row = 1; row <= numberOfRows; row++) {
for (int column = 1; column <= row; column++) {
System.out.print(column + " ");
}
System.out.println();
}
// Step 2: rows get shorter again, without repeating the longest row
for (int row = numberOfRows - 1; row >= 1; row--) {
for (int column = 1; column <= row; column++) {
System.out.print(column + " ");
}
System.out.println();
}
}
}
Output (with sample input)
Enter the number of rows: 4 1 1 2 1 2 3 1 2 3 4 1 2 3 1 2 1
5. Summary
- The outer loop picks the row; the inner loops print the spaces and the numbers for that row.
- Work out how many spaces and which numbers each row needs, then write one inner loop for each.
- Keep
numberOfRowsin a variable, so the same program can print the pattern in any size.
Related Programs
Was this tutorial helpful?