Java Program to Print Sandglass Character Pattern
In this program we print a sandglass (hourglass) of letters. The top half narrows from A B C D E to a single E, and the bottom half widens back out.
Like every pattern program, it is built from nested loops: the outer loop picks the row, and the inner loops print what goes on that row. Java stores a char as a number, so adding to 'A' and casting back with (char) gives the following letters.
1. The Pattern
For 5 rows the program prints:
Pattern
A B C D E
B C D E
C D E
D E
E
E
D E
C D E
B C D E
A B C D E
2. How the Program Works
Here is what each printed line is made of when numberOfRows is 5:
| Line | Leading spaces | Printed after the spaces |
|---|---|---|
| 1 | 0 | A B C D E |
| 2 | 1 | B C D E |
| 3 | 2 | C D E |
| 4 | 3 | D E |
| 5 | 4 | E |
| 6 | 4 | E |
| 7 | 3 | D E |
| 8 | 2 | C D E |
| 9 | 1 | B C D E |
| 10 | 0 | A B C D E |
- Both parts print
row - 1spaces and then the letters from the row's letter up to the last letter, each followed by a space. - Step 1 counts
rowup from 1 tonumberOfRows, so the rows get shorter. - Step 2 counts
rowback down fromnumberOfRowsto 1, so the rows get longer again. Both parts print the single E row, so it appears twice in the middle. System.out.println()moves to the next line after each row.
3. Java Program
public class Pattern21 {
public static void main(String[] args) {
int numberOfRows = 5;
// Step 1: top half, rows get shorter
for (int row = 1; row <= numberOfRows; row++) {
for (int column = 1; column < row; column++) {
System.out.print(" ");
}
for (int column = row; column <= numberOfRows; column++) {
System.out.print((char) ('A' + column - 1) + " ");
}
System.out.println();
}
// Step 2: bottom half, rows get longer again
for (int row = numberOfRows; row >= 1; row--) {
for (int column = 1; column < row; column++) {
System.out.print(" ");
}
for (int column = row; column <= numberOfRows; column++) {
System.out.print((char) ('A' + column - 1) + " ");
}
System.out.println();
}
}
}
Output
A B C D E
B C D E
C D E
D E
E
E
D E
C D E
B C D E
A B C D E
4. Print the Pattern for Any Number of Rows
To let the user choose the size of the pattern, read the number of rows with a Scanner. The loops stay the same.
import java.util.Scanner;
public class Pattern21Input {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
System.out.print("Enter the number of rows: ");
int numberOfRows = scanner.nextInt();
scanner.close();
// Step 1: top half, rows get shorter
for (int row = 1; row <= numberOfRows; row++) {
for (int column = 1; column < row; column++) {
System.out.print(" ");
}
for (int column = row; column <= numberOfRows; column++) {
System.out.print((char) ('A' + column - 1) + " ");
}
System.out.println();
}
// Step 2: bottom half, rows get longer again
for (int row = numberOfRows; row >= 1; row--) {
for (int column = 1; column < row; column++) {
System.out.print(" ");
}
for (int column = row; column <= numberOfRows; column++) {
System.out.print((char) ('A' + column - 1) + " ");
}
System.out.println();
}
}
}
Output (with sample input)
Enter the number of rows: 4 A B C D B C D C D D D C D B C D A B C D
Note: there are only 26 letters. Past Z,
(char) ('A' + 26) is [, not a letter, so keep the number of rows small enough that the pattern never needs a letter after Z.5. Summary
- The outer loop picks the row; the inner loops print the spaces and the letters for that row.
(char) ('A' + k)gives the letterkplaces after A.- Keep
numberOfRowsin a variable, so the same program can print the pattern in any size.
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